Equations of a Circumference: A Comprehensive Guide
Circumference as Geometric Locus
The geometric locus is a group of points that satisfy certain geometric conditions. The geometric locus of the circumference is the group of points that are at the same distance r from a point called the center.
Example
Determine the geometric locus that describes a point that moves a distance of 4 units around a fixed point with coordinates (0,0).
Steps
- Identify the fixed point on the plane.
- Draw a point at a distance of 4 units to each of the four cardinal points.
- Join the drawn points as a circle at 4 units from the fixed point (0, 0).
Answer
The resulting figure is a circumference with center at (0, 0) and radius equal to 4.
Types of Equations of the Circumference
There are three ways to represent the equation of the circumference:
- Canonical form
- Ordinary form
- General equation
For the canonical form, the center of the circumference is considered to be at the origin C (0, 0), the distance is from the center to any of the points of the circumference P(x,y), and its radius is a length equal to r:
Given points C(0,0) and P(x,y), the distance between them will be the length of the radius. Applying the formula of the distance between two points, we have:
By raising both sides of the equation to the square, we have:
This expression is known as the equation of the circumference with its center at the origin, also known as the canonical form.
Example
Determine the equation of the circumference with its center at the origin and a radius equal to 7.
Steps
- If the center of the circumference is at the origin, then the following equation is used:
- Substitute the value of the radius in the previous equation:
Answer
Raise the radius to the square to obtain the following expression:
Example
Determine the equation of the circumference that contains point (2,5) and its center is at the origin C(0,0).
Steps
- In this exercise, the length of the radius is not known, it should be determined with the given data and the following equation:
- Once the radius has been established, substitute its value in the canonical form of the equation of the circumference.
Answer
The square is canceled with the square root and the following equation is obtained:
The equation of the circumference in its ordinary form has its center outside the origin at C(h,k) and its radius is the distance from the center to any point within the circumference P(x,y):
Calculating the distance from the center to the point for obtaining the radius, we have:
Both sides of the equality are raised to the square:
This equation is known as the equation of the circumference with its center outside the origin, also known as the ordinary form of the equation of the circumference.
Example
Determine the equation of the circumference with center at (-1,3) and with radius length equal to 6.
Steps
- To find the equation, use the following expression because its center is outside the origin.
- Substitute the center C(-1,3) and the radius in the previous equation:
- Apply the rules of signs and raise to the square:
Answer
Example
Determine the equation of the circumference with center at (-2,-1) that passes through point P(2,4).
Steps
- Obtain the value of the radius with the following equation:
- Apply the rules of signs and obtain the square root:
- Knowing the value of the radius and the center C(-2,-1), substitute the values in the following equation:
Answer
The resulting equation is:
To obtain the general form of the circumference equation, we start from its ordinary form.
We work with the binomials to the square and the resulting equation is as follows:
Making the equation equal zero, we have:
Substitute to obtain the following:
The previous expression is known as the general equation of the circumference.
From the value of the radius, we can determine its graphic representation:
- If r < 0, then the equation does not represent a circumference, so it cannot be graphically represented because there are no negative radiuses.
- If r = 0, then it represents a point which is represented by the coordinates of the center.
- If r > 0, the geometric locus is from a circumference and it is possible to represent it in a plane.
Example
Given the equation of the circumference on ordinary form, obtain the equation in its general form.
Steps
- Expand binomials to the square, as follows:
- Arrange the quadratic terms first, then the linear ones and finally, the equation must equal to zero:
Answer
Simplify the expression by adding all independent terms. The resulting equation is:
Equation of a Circumference that Satisfies Three Conditions
Consider the case in which you have a circumference that passes through three points A(x1,y1), B(x2,y2) and C(x3,y3), these three points are substituted in the equation of the circumference in its general form where the missing values are D, E and F. In this way, you will obtain a system of three equations with three variables to solve.
You can see this case illustrated in the following example.
Example
Determine the equation of the circumference that passes through points O(2,-2), P(3,1) and Q(-3,-2).
Steps
- Substitute the points in the general formula:
- Evaluate the values of each of the equations and simplify as follows:
- You have 3 equations with three variables. You can use any method you know to solve the system of equations: substitution, addition or elimination.
- Applying the elimination method, you add equations P and Q:
- Equation O is multiplied by 3 and equation Q is multiplied by 2, then both are added:
- Equation R is multiplied by -10 and is added to equation S for then solving for variable F:
- Knowing the value for variable F, substitute in equation S and solve for variable E:
- Knowing the values F = -12 and E = -1, substitute in any of the three original equations, O, P or Q to obtain the value for D.
Answer
Substitute the values for D, E and F in the general equation of the circumference to obtain the following expression:
Polar Form of the Circumference Equation
To obtain the polar form of the equation of the circumference, you should express it in terms of r and , and substitute and . The following example can help you understand this concept.
Example
Given the equation of the circumference , obtain its polar form.
Steps
- Expand binomials to the square, as follows:
- Substitute and in the resulting expression:
- From the first two terms, take out r2 as a common factor:
- Considering the identity =1
substitute it by 1 in the equation and factorize:
Answer
The equation in its polar form is: