Understanding Lines and Angles in Analytic Geometry

Length of a Segment from a Point to a Line

The shortest distance from a point P (x1, y1) to a line Ax + By + C = 0 is given by the following expression:

e4-1.gif

In this expression, (x,y) represent the point from which we want to measure the distance, and A, B, and C are the coefficients of the line.

The conditions to consider are the following:

  • If the value of C is not equal to 0, the sign of the radical is the opposite of C.
  • If C=0 and B is not equal to 0, the radical will have the same sign as B.
  • If C=B=0, the radical and A will have the same sign.

Example

Determine the equation of the line that contains the point (2, 1), knowing that there is a minimal distance between this point and point (4, 3).

Steps

  1. Procedure
  2. Determine the distance between both given points.
    e4-2.gif
  3. Calculate the slope of the line that represents the distance between the points.
    e4-3.gif
  4. Consider that the calculated slope is from the line perpendicular to the line from which we want to obtain an equation.

Then, based on the perpendicularity theorem, we consider the slope calculated in the previous step as reciprocal and with the opposite sign:

e4-4.gif

Using the point-slope equation of the line, we obtain the requested equation.

e4-5.gif

To prove, we obtain the distance from point (4, 3) and the line that resulted from the previous step.

e4-6.gif

Rationalize the resulting value.

e4-7.gif

This is the same distance between the points obtained in the first step.

Answer

The equation of the line is:

e4-8.gif

Angle Between Two Lines

Let A1x + B1y + C1= 0 and A2x + B2y + C2 = 0 be two lines that intercept at one point and form an angle e4-9.gif obtained by the following expression:

e4-10.gif

Where m1 is the slope from which the angle is first measured and m2 is the slope of the line where the angle is finally measured. The angle is measured counterclockwise.

Example

Calculate the angle formed between the lines 3x-4y+5=0 and x+6y-3=0. Graph the lines and the angle between them.

Steps

  1. Procedure
  2. First, graph the lines for determining the order of the slopes in the angle’s formula. In order to graph them, obtain the intersections with each of their axes.
    e4-11.gif
  3. Sketch the obtained points
    e4-2.jpg
  4. Find the slopes of the lines by rearranging the equation as slope-ordinate form.
    e4-12.gif
  5. Substitute the slopes in the formula to determine the angle.
    e4-13.gif

Answer

e4-14.gif

Equation of a Family of Lines

The equations of the line have been expressed in different forms:

e4-15.gif

Each of them has two constants with a specific geometric importance, known as parameters. For example, in the first equation, the parameters are m and b, while in the second, the parameters are a and b.

A linear equation with one parameter represents a group of lines that have the same characteristic, for example:

e4-3.jpg

In this example, the equation represents all those lines that cut the y axis at y=5, regardless of its inclination angle or slope.

Example

Write the equation of the family of lines that pass through point (5, 3).

Steps

  1. Procedure
  2. Substitute the given point into the equation.
    e4-16.gif
  3. Multiply the m value by the expression contained within the parenthesis.
    e4-17.gif

Answer

The equation of the family of lines that pass through point (5, 3) is: e4-18.gif where m is the value of the slope.

Polar Form of the Equation of a Line

The general equation of the straight line e4-19.gif can be transformed into its polar form by substituting e4-20.gif and e4-21.gif into the following equation:

e4-22.gif

The equation of the line that passes through the origin as the form e4-23.gif will be expressed as:

e4-24.gif

Example

Transform the equation 6x – 2y + 8 = 0 into its polar form.

Steps

  1. Procedure
  2. Substitute the x and y values in the equation by their relation in polar form.
    e4-25.gif
  3. Solve for r in the expression, in order to obtain the polar equation of the line.
    e4-26.gif

Answer

e4-27.gif